(3x-7)^2+6x=14

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Solution for (3x-7)^2+6x=14 equation: 



(3x-7)^2+6x=14

We move all terms to the left:

(3x-7)^2+6x-(14)=0

We add all the numbers together, and all the variables

6x+(3x-7)^2-14=0

We move all terms containing x to the left, all other terms to the right

6x+(3x-7)^2=14

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